How do i use quoting with $* and $@ in bash?

giraffelife

These two parameters work differently.

If the Initial field separator is a comma, you can see the difference. See the following script to explain.

IFS=,
echo "$*"

myargs()
{
   echo "$# args."
}

myargs apples pears bananas
myargs "$*"
myargs "$@"

Run the script

$ ./bash.arglist apple pears bananas
apple,pears,bananas
3 args.
1 args.
3 args.

$# - number of args is 3
$* - seen as apple,pears,bananas
$@ - seen as apples pears bananas