How do i display the all systemd manager properties?
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show [PATTERN...|JOB...] Show properties of one or more units, jobs, or the manager itself. If no argument is specified, properties of the manager will be shown. If a unit name is specified, properties of the unit is shown, and if a job id is specified, properties of the job is shown. By default, empty properties are suppressed. Use --all to show those too. To select specific properties to show, use --property=. This command is intended to be used whenever computer-parsable output is required. Use status if you are looking for formatted human-readable output.
By default, without any arguments, all systemd manager properties are shown.
$ systemctl show
To be more specific, use the
-p
option:-p, --property= When showing unit/job/manager properties with the show command, limit display to properties specified in the argument. The argument should be a comma-separated list of property names, such as "MainPID". Unless specified, all known properties are shown. If specified more than once, all properties with the specified names are shown. Shell completion is implemented for property names. For the manager itself, systemctl show will show all available properties. Those properties are documented in systemd- system.conf(5). Properties for units vary by unit type, so showing any unit (even a non-existent one) is a way to list properties pertaining to this type. Similarly showing any job will list properties pertaining to all jobs. Properties for units are documented in systemd.unit(5), and the pages for individual unit types systemd.service(5), systemd.socket(5), etc.
$ systemctl show -p LogLevel LogLevel=info
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